Question

The head of the shadows of a 15 m tree and a 45 m building are at the same point when the Sun is at an angle of 45° . Find the distance between the tree and the building.
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Answer 1

$\sf\small\red{Given:-}$

• Shadow = 15m.

• Building = 45m.

• Angle = 45° .

$\sf\small\red{Find:-}$

• Find the distance between the tree and the building.

$\sf\small\red{Solution:-}$

First finding AB:-

$\rm\rightarrow\frac{BD}{AB} = tan 45°$

$\rm\rightarrow\frac{15}{AB} = 1$

$\rm\rightarrow \fbox \pink{ AB = 15}$

Now, Find AC :-

$\rm\rightarrow \frac{EC}{AC} = Tan \: 45°$

$\rm\rightarrow \frac{AC}{EC} = Tan \: 45°$

$\rm\rightarrow EC = AC$

$\rm\rightarrow\fbox\pink{ AC = 45m}$

Final value,

$\rm\rightarrow BC = AC - AB$

$\rm\rightarrow 45 - 15$

$\rm\dashrightarrow 30$

$\rule{36mm}{1mm}$