The heap of rice is in the form of the cone of base diameter 24cm and height 3.5m find the volume of the rice and at wch rate of canvas cloth is require to just cover the heap
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Volume of rice = volume of cone = 1/3πr²h
Here , r = 12 [ ∵ diameter = 24 m ] and h = 3.5m
Now, volume of rice = 1/3 × 22/7 × (12)² × 3.5 m³
= 1/3 × 22/7 × 12 × 12 × 7/2 m³
=22 × 24 = 528 m³
Again, area of canvas cloth = curve surface area of cone = πrl
Here l = √(r² + h²)
= √{12² + 3.5²} = √{144 + 12.25 } = √{156.25} = 12.5 m
∴ area of canvas cloth = 22/7 × 12 × 12.5 m²
= 471.42 m²
Here , r = 12 [ ∵ diameter = 24 m ] and h = 3.5m
Now, volume of rice = 1/3 × 22/7 × (12)² × 3.5 m³
= 1/3 × 22/7 × 12 × 12 × 7/2 m³
=22 × 24 = 528 m³
Again, area of canvas cloth = curve surface area of cone = πrl
Here l = √(r² + h²)
= √{12² + 3.5²} = √{144 + 12.25 } = √{156.25} = 12.5 m
∴ area of canvas cloth = 22/7 × 12 × 12.5 m²
= 471.42 m²
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