The heart beats once in 0.8 second. find the number of times the heart beats in the life of 60 years of a man
Answers
Answered by
59
As , 60 years = 60× 365 = 21900 days
21900 days = 21900 × 24 = 525600 hr
525600 hr = 525600 × 60 = 31536000 min
31536000 min = 31536000 × 60 =1892160000 sec
As, given
In 0.8 sec ,no. of time heart beats = 1
In 1892160000 sec, no. of time heart beats = 1 × 1892160000 /0.8
21900 days = 21900 × 24 = 525600 hr
525600 hr = 525600 × 60 = 31536000 min
31536000 min = 31536000 × 60 =1892160000 sec
As, given
In 0.8 sec ,no. of time heart beats = 1
In 1892160000 sec, no. of time heart beats = 1 × 1892160000 /0.8
tiara5:
Thanx
welcome
Answered by
7
Answer:
Explanation: the correct answer is 3942 x 10^5 beats
Attachments:
Similar questions