Question

the heat dissipated in a resistance R is H =I^2 R T / 4.2 calorie .if maximum error inthe measurements of current I,resistance R and time t are 2% 1% 1% respactively .what is the maximum error in dissipated heat​

Answer 1

Answer:

6%

Explanation:

H=I^2RT

H=2(DELTA I/I)+(DELTA R/R)+(DELTA T/T)

H=2(2)+(1)+(1)

H=6%

Answer 2

Answer:0.24

Explanation:l^2rt÷4.2 (joule /calorie )=0.24