The heat evolved in combustion of 112 litres of water gas at ntp
Answers
the heat evolved during the combustion of...
the heat evolved during the combustion of 112 litre of water gas (mixture of equal volume of H2 and CO) is H2 + 1/2O2 gives rise to H2O ; delta H = -241.8 ; CO + ½ O2 gives rise to CO2 ;delta H = -280kj/mol
a)-241.8kj/mol
b)-143kj/mol
c)+286kj/mol
d)+143kj/mol
one year ago
Answers : (1)
photos YouTube all by the reaction of hydrogen gas and carbon monoxide gas is 241.8 + 283 that is equal to 5 24.8 kilojoule.
Now volume occupied by a gas at STP is 22.4 litres
Volume of hydrogen gas is equal to volume of carbon monoxide gas is equal to 1 1 2 1 / 2 is equal to 56 litres.
Number of balls of each gas is equal to 56 divided by 22.4 litres.
Jaipur number of moles of Ethane gas is 56 divided by 22.4 litres
Is equal to 2.5 moles of heat evolved by the reaction of 1 mole of each gas is equal to 524.8 kilo joule.
David award by the reaction of 2.5 moles of each gas is equal to 520 4.8 into 2.5 is equal to 13 12 kilo joules