Question

?The heat generated in a
bearing for given data will be
shaft dia= 150 mm. Speed is
1500 RPM, load = KN
coefficient if friction = 0.02
will be (formula = mwV)​

Answer 1

Explanation:

The heat generated in a bearing for given data will be shaft dia= 150 mm. Speed is 1500 RPM, load = kN coefficient if friction = 0.02 will be (formula = mwV)

Answer 2

Answer:

The heat generated in a bearing is 235.6W.

Explanation:

The heat generated due to friction,

$H = \mu WV$ (1)

Where,

H=heat generated

μ=coefficient of friction

W=load

V=rubbing velocity

From the question we have,

The diameter of the shaft(d)=150mm=150×10⁻³m

The load(W)=1kN=10³N

The coefficient of friction(μ)=0.02

The speed(N)=1500RPM

First, let's calculate the rubbing velocity which is given as,

$V=\frac{\pi d N}{60}$  (2)

By inserting the values in equation (2) we get;

$V=\frac{\pi\times 150\times 10^-^3\times 1500}{60}$

$V=11.78m/s$     (3)

We get the following results by plugging all of the values into equation (1):

$H = 0.02\times 1000\times 11.78$

$H=235.6W$

Hence, the heat generated in a bearing is 235.6W.

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