Question

The heat generated in a circuit is dependent upon the resistance current and time for which the current is flown . If the error in measuring the above is 1%,2%,1%, respectively, the maximum error in measuring the heat is

Answer 1

Answer:

6%.

Explanation:

Since, from the question we have that the error for the current i is 2% , for resistance is 1% and for the time t is also 1%.

We know that when heat is dissipated in the circuit the heat will be i^2Rt since, the heat loss is mainly through the wires per unit time.

So, H= i^2Rt.

Or, ΔH/H = 2Δi/i + ΔR/R +Δt/t.

Now, on substituting the value of error we will get that.

ΔH/H = 2*2% + 1*1% + 1*1% which on solving we will get that error of heat production is 6%.

Answer 2

Q = I^2 RT

Where

Q is the heat

I - current

R - resistance

T - time

∆Q/Q = 2×∆I/I + ∆R/R + ∆T/T

= 2× 2 + 1 + 1

= 4 + 1 + 1

= 6%

Hope it helps

Thank you