The heat of combustion of solid benzoic acid at constant volume is -321.3kj at 300k . the heat of combustion at constant pressure is?
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C6H5COOH(s) + 15/2 O2(g) ----> 7CO2(g) + 3H2O(l)
1 mol 15/2 mol 7 mol
△ng = np - nR = 7 - (15/2) = - 0.5 mol ;
qv = -312.3 KJ
qp = qv + △ng RT ---(1)
qp = -312.3 + (-0.5) x R x
(273 + 27 i.e, 300K)
= -312.3 - 150 R
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Answer:
-321.3-150R
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