Physics, asked by malvisharma2, 10 months ago

the height above the surface of the earth where acc. due to gravity is 1/64 of its value at surface of the earth is approximately

Answers

Answered by RajivShastry
1

g inversely proportional to (R+h)²

64 = [(R+h)/R]²

8 = 1 + h/R

h = 7R

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