Question

The height and radius of a cone are 14 cm and 6 cm respectively. find the volume ofthe cone.​

Answer 1

Given :-

• The height and radius of a cone are 14 cm and 6 cm respectively.

To find :-

• Volume of a cone

Solution :-

• Height of cone = 14cm

• Radius of cone = 6cm

As we know that

→ Volume of cone = ⅓ πr²h

Where " r " is radius and " h " is height of a cone.

According to the question

→ Volume of cone

→ ⅓ πr²h

Put the value of height and radius

→ ⅓ × 22/7 × (6)² × 14

→ ⅓ × 22 × 6 × 6 × 2

→ 22 × 2 × 6 × 2

→ 44 × 12

→ 528 cm³

Hence,

• Volume of cone is 528cm³

Extra Information :-

• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cylinder = πr²h
• Volume of cube = a³
• Volume of cone = ⅓ πr²h
• Volume of cuboid = l × b × h
• C.S.A of cone = πrl
• T.S.A of cube = 6a²
• C.S.A of cube = 4a²
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cuboid = 2(l + b)h

Answer 2

Question :

‏‏‎ ‎

The height and radius of a cone are 14 cm and 6 cm respectively. find the volume of the cone.

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Answer :

‏‏‎ ‎

Given :

‏‏‎ ‎

• Height of the cone = 14 cm

• Radius of the cone = 6 cm

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To find :

‏‏‎ ‎

• Volume of the cone

‏‏‎ ‎

Formula :

‏‏‎ ‎

Volume of the cone = $\frac{1}{3} π r^2 h cu units$

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According to the question :

‏‏‎ ‎

Volume = $\frac{1}{3} π r^2 h cu\:units$

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Substituting values of,

‏‏‎ ‎

• Height = 14 cm

• Radius = 6 cm

‏‏‎ ‎

We get :

‏‏‎ ‎

⟹ Volume = $\frac{1}{3} × \frac{22}{7} × r^2 × h × cu\:units$

⟹ $\frac{1}{3} × \frac{22}{7} × 6^2 × 14$

⟹ $\frac{1} {\cancel{3}} × \frac{22} {\cancel{7}} × \cancel{6}× 6 × \cancel{14}$

⟹ $22 × 2 × 6 × 2$

⟹ $\bold{528 cm^3}$

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So, It's Done !!