Question

The height at which g will be th1/4 of its value at the earth surface is​

Answer 1

Explanation:

The acceleration due to gravity at a height h above Earth's surface is:

g

h

=

(1+

R

h

)

2

g

As g

h

is 4% of g so g

h

=0.04g

⇒0.04g=

(1+

R

h

)

2

g

⇒(1+

R

h

)

2

=

0.04

1

=25

⇒1+

R

h

=5

⇒

R

h

=4⇒h=4R.