The height from the earth surface at which the value of acceleration due to gravity reduces to one fourth of its value at earth surface (radius of earth = 6400 km)
1-6400 km
2- 2649 km
3- 2946 km
4-1600 km
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Answer:
1 = 6400 is the answer
Explanation:
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Dear student
Given :-
- acceleration due to gravity = 1/4 Ge
To find :-
- the value of height
Solution :-
Consider the straight forward relationship between radius and acceleration due gravity by the formula;
gh = g R²/ ( R + h )²
So, from the given condition, we have;
g/ 4 = g R² /( R + h )²
1/4 = R²/ ( R + h )²
1/2 = R / ( R + h )
R + h = 2 R
h = 2R - R
h = R
h = 6400 km
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