Question

the height (in cm)of 9 students of a class are as follows:155,160,145,147,152,144,148 find the median of this data
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Answer 1

Answer :

$\large \implies 148$

Solution :

Firstly we have to arrange in a order ,

So, it will be :-

144, 145, 147, 148, 152, 155, 160

Here, Number of terms is 7 .

$\large \sf Median_{odd \: number} = \frac{n+1}{2}$

$\large \sf Median = \frac{7+1}{2} \\ \\ \large\sf \implies 4^{th} term$

4th term is 148 .

Therefore , Median is 148 .

Answer 2

Answer :

➠ $\large \tt \underline{148}$

Solution :

☞ Given :

The height (in cm) of 9 students of a class are as follows:155, 160, 145, 147, 152, 144, 148.

☞ To Find :

Median

$\; \; \; \: \; \; ━━━━━━━━━━━━━━━━━━━━━$

Let's solve,

»» Firstly we have to arrange the given data in a order.

After Arranging the given data

⇝ 144, 145, 147, 148, 152, 155, 160

»» There are 7 number of terms. So, n = 7.

We know that ,

If n is any odd number =

$\large \color{red} \boxed{\tt Median = {\frac{n + 1}{2} }^{th} term }$

If n is any even number =

$\large \color{red} \boxed{\tt Median = {\frac{n }{2} }^{th} term +{(\frac{n }{2} + 1)}^{th} }$

Here, n is Odd.

So,

$\large \sf Median = {\frac{n+1}{2}}^{th} term \\ \\ \large \implies {\frac{7+1}{2}}^{th} term \\ \\ \implies \sf 4^{th} term$

Here 4th term is 148

$\sf 144, 145, 147, \boxed{148}, 152, 155, 160$

Therefore,

Median of this data is 148.