Question

The height of a circular cone increased by 25% and radius of its base is increased by 10% find the percentage increase in volume of the cone.​

Answer 1

Answer:

Let the radius and the height of the cone be r and h.

So volume of the cone (1/3)πr^2h

After 10% increase new radius = (110/100)r = (11r/10)

Similarly after 10% increase new height = (110/100)h = 11h/10

So new volume (1/3)π(11r/10)^2(11h/10)

= (121/100)(11/10)(1/3)πr^2h

= (1331/1000)(1/3)πr^2h

So increase in the volume

= (1331/1000)(1/3)πr^2h-(1/3)πr^2h

= (331/1000)(1/3)πr^2h

So percentage of increase in the volume =

[{(331/1000)(1/3)πr^2h}/{(1/3)πr^2h}]×100

= (331/10)% = 33.1%

Step-by-step explanation:

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Answer 2

Answer:

answer for the given problem is given