Question

The height of a cone is 15 cm if its volume is 1570 cm cube find the radius of the base

Answer 1

ANSWER:--------

given :-

height of the cone = 15cm

volume of the cone = 1570cm³

formula to Find the volume of a cone is 1/3πr²h

therefore 1/3πr²h = 1570cm³

→ 1/3 × 22/7 × r² × 15 = 1570cm³

→ 22/7 × 5 × r² = 1570cm³

→110/7 × r² = 1570

→ r² = 1570 × 7/110

→ r² = 10990/110

→ r² = 99.90cm (approximately)

hence, the radius of the cone = √99.9 = 9.9cm

T!–!ANKS!!

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{Given-}}}$⠀

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• Height = 15cm
• Volume = 1570cm³

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$\sf{\underline{\red{Find-}}}$

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• Radius?

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$\sf{\underline{\red{Answer-}}}$

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• The radius of the base is 10cm.

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$\sf{\underline{\red{Explanation-}}}$

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$\sf{\underline{\green{Formula\:used\:here-}}}$

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$\: \: \: \: \: \bigstar \: \: \: \: \: \boxed{\sf{\pink{ \dfrac{1}{3} \times \pi \times {r}^{2} \times h }}}$

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$\sf{\underline{\blue{Now\: putting\:the\:values-}}}$

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$\begin{gathered}:\implies\sf\:1570= \dfrac{1}{3} \times 3.14 \times {r}^{2} \times 15\end{gathered}$

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$\begin{gathered}:\implies\sf1570 \times 3 = 3.14 \times {r}^{2} \times 15 \end{gathered}$

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$\begin{gathered}:\implies\sf {r}^{2} = \dfrac{1570 \times 3}{3.14 \times 15} \end{gathered} \:$

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$\begin{gathered}:\implies\sf {r}^{2} = \dfrac{4710}{47.1} \end{gathered} \:$

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$\bigstar \: \sf \: Multiply \: by \: 10 \: to \: remove \: decimal$

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$\begin{gathered}:\implies\sf {r}^{2} = \dfrac{4710 \times 10}{47.1 \times 10} \end{gathered} \:$

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$\begin{gathered}:\implies\sf {r}^{2} = \dfrac{47100}{471}=100 \end{gathered}$

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$\begin{gathered}:\implies\sf {r}^{2} =100 =r \sqrt{100} \end{gathered}$

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$\begin{gathered}:\implies\sf \: r=10 \: cm \end{gathered}$

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• Therefore the value of radius of the base is 10cm.

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