Math, asked by prem2928, 1 year ago

the height of a cone is 30cm a small cone is cut off at the top by a plane parallel to its base the ratio of the volume of small cone of the volume of the given cone is 1: 27 find the height of the first formed​

Answers

Answered by ZiaAzhar89
11
\mathbb{\huge{\purple{Zia\: Dilliwali}}}
\huge\boxed{\large\boxed{\large\boxed{\mathbb{BRAINLIST!}}}}...

Hello !

Let the Height and Radius of the Big cone be H cm and R cm 

And of small cone be h cm and r cm

Let the volume of the big cone be V and of small cone be v

The cone is cut from the big cone then , they both cones would be similar to each other and according to the property of the similarity ,

H/R = h/r

⇒ h= Hr/R

⇒ h = 30 r/R               ...............................eqn 1

Volume of the cone = 1/3 πr²h

v/V = r²h/R²H = 1/27

⇒ r²h = 30 R²/27

⇒ h=10 R²/9 r²            ...........................      eqn 2

On substituting the value of the h from eqn 1 in eqn 2 we get : -

30r/R = 10R²/9r²

⇒ r³/R³ = 1/27

⇒ r/R = 1/3

Substituting this ratio in eqn 1 we get :-

h = 30 × 1/ 3

⇒ h = 10 cm                                                                     Ans.

Hence, Height of the small(cut) cone is 10 cm            Ans.

And the Height of the Frustum is 30-10 = 20 cm         Ans.

I hope my satisfies your curiousity and the answer is I hope so !

Please mark it as the brainliest if you are satisfied !

Thank you !

Have a nice day !

prem2928: thanks..
Answered by singhdipanshu2707200
0

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