The height of a cylinder is double of its diameter and it's volume is 539 cu. cm. What is the diameter of its base in cm?
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Let the diameter of the Cylinder is X.
Height of Cylinder is 2X.
Radius of Cylinder = D/2 = X/2.
Volume of Cylinder = πr²h
539 = 22/7×X/2×X/2×X
539 = 22X³/28
22X³ = 539×28
22X³ = 15092
X³ = 15092/22
X³ = 686
X = ³✓686
FIND THE CUBE ROOT OF 686.
THEN THE DIAMETER OF THE CYLINDER IS THE CUBE OF 686.
THEREFORE,
RADIUS = D/2
PUT THE VALUE OF DIAMETER AND DIVIDE BY 2 THEN U WILL GET THE RADIUS OF THE BASE OF THE CYLINDER.
Height of Cylinder is 2X.
Radius of Cylinder = D/2 = X/2.
Volume of Cylinder = πr²h
539 = 22/7×X/2×X/2×X
539 = 22X³/28
22X³ = 539×28
22X³ = 15092
X³ = 15092/22
X³ = 686
X = ³✓686
FIND THE CUBE ROOT OF 686.
THEN THE DIAMETER OF THE CYLINDER IS THE CUBE OF 686.
THEREFORE,
RADIUS = D/2
PUT THE VALUE OF DIAMETER AND DIVIDE BY 2 THEN U WILL GET THE RADIUS OF THE BASE OF THE CYLINDER.
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