the height of a parallelogram is three-eighths of its base. If the area of the parallelogram is 96cm², find its height and base.
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Let the base of the parallelogram be x
and the height= 3/8x
Area of the parallelogram= 96 cm^2
Since ar. of a parallelogram= 1/2×base×height
Therefore,
96= 1/2×x×3/8x
96= 3/16x^2
x^2= 96×16/3
x^2= 512
x= (512)^1/2
x= 16(2)^1/2
Therefore the base= 16(2)^1/2
Height= 3/8×16(2)^1/2= 6(2)^1/2
and the height= 3/8x
Area of the parallelogram= 96 cm^2
Since ar. of a parallelogram= 1/2×base×height
Therefore,
96= 1/2×x×3/8x
96= 3/16x^2
x^2= 96×16/3
x^2= 512
x= (512)^1/2
x= 16(2)^1/2
Therefore the base= 16(2)^1/2
Height= 3/8×16(2)^1/2= 6(2)^1/2
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