Question

The height of a parallelogram is three-eighths of its base. If the area of the parallelogram is 96cm², find its height and base

Answer 1

Let the base of the parallelogram be x
and the height= 3/8x
Area of the parallelogram= 96 cm^2
Since ar. of a parallelogram= 1/2×base×height 
Therefore, 
96= 1/2×x×3/8x
96= 3/16x^2
x^2= 96×16/3
x^2= 512
x= (512)^1/2
x= 16(2)^1/2 
Therefore the base= 16(2)^1/2
Height= 3/8×16(2)^1/2= 6(2)^1/2

Answer 2

Let the base of the parallelogram be x

and the height= 3/8x

Area of the parallelogram= 96 cm^2

Since ar. of a parallelogram= 1/2×base×height  

Therefore,  

96= 1/2×x×3/8x

96= 3/16x^2

x^2= 96×16/3

x^2= 512

x= (512)^1/2

x= 16(2)^1/2  

Therefore the base= 16(2)^1/2

Height= 3/8×16(2)^1/2= 6cm

Hope this was helpful for you