The height of a parallelogramis one third of its base.If thearaof the parallelogram 192cm2 find he8ght and base
Answers
Answered by
2
Answer:
area of a parallelogram is = base×height.
base= y
height=1/3y
area=192cm²
192 = y × 1/3y
192=y²/3
192×3 =y²
576 =y²
√576 = y
24 =y
BASE = 24
HEIGHT= 1/3y = 1/3 ×24
=8
Answered by
2
SOLUTION;.....®️
We know that the Area of ||gm= Base×height
Now let us assume that the base of the ||gm be Bcm, then the height of the ||gm will be 1/3Bcm
So, B×B/3= 192cm^2
= B^2= 192×3
= B^2= 576
= B= √576
= B = 24cm
So, the base of the ||gm= 24cm
And height= 1/3 of 24= 8cm Ans..
MARK BRAINLIEST...⛄
We know that the Area of ||gm= Base×height
Now let us assume that the base of the ||gm be Bcm, then the height of the ||gm will be 1/3Bcm
So, B×B/3= 192cm^2
= B^2= 192×3
= B^2= 576
= B= √576
= B = 24cm
So, the base of the ||gm= 24cm
And height= 1/3 of 24= 8cm Ans..
MARK BRAINLIEST...⛄
Similar questions