the height of a right circular cone is 8 cm and the diameter of its base is 12 cm .
1) the slant height of the cone
2) the total surface area of the cone
3) the volume of the cone
Answers
Step-by-step explanation:
daimeter=12cm
radius=12÷2=6cm
slant height =?
l^2=h^2+r^2
l^2=8^2+6^2
l^2=64+36=100
l^2=100
l=\sqrt[100]
l=10
slant height=10cm
total surface area of cone=\pi*r(l+r)
3.14*6(10+6)
3.14*6*16
310.44cm^2
(3)volume of cone =1by3*\pi*r^2*h
1by3*3.14*6*6*8
=904.32÷3
=301.44cm^3
I hope it helpful
Step-by-step explanation:
1. slant height L^2=h^2+r^2
=8^2+6^2
=64+34
=100
L=✓100
L=10
2. TSA=πr[h+r]
=3.14×6(10+6)
=3.14×6×16
=310.44cm^2
3.volume=1/3πr^2h
=1/3×3.14×6^2×8
=1/3×3.14×6×6×8
=904.32÷3
=301.44cm^3
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