Question

the height of a right circular cylinder is 6m. three times the sum of the areas of its two circular faces Is twice the area of the curved surface. find the radius of its base.​

Answer 1

Answer :- 4 m

Given that,

➜ Height of a right circular cylinder, h = 6 m

Also,

⇒ Three times the sum of the areas of its two circulars faces is twice the area of the curved surface.

We know,

⇒ Area of circular face of a cylinder = πr²

and,

⇒ Curved surface area of cylinder = 2πrh

∴ 3( 2πr² ) = 2(2πrh)

⇒ 6πr² = 4πrh

⇒ 3r² = 2rh

⇒ 3r = 2h

⇒ 3r = 12

⇒ r = 4 m

Hence, The radius of the base of cylinder is 4 m.

Some Information :-

• Volume of Cylinder = πr²h
• Volume of Cone = 1/3 πr²h
• Volume of Cube = Side³
• Volume of Cuboid = l × b × h
• Curved surface area of Cone = πrl
• Curved surface area of cube = 4 × side²

Answer 2

EXPLANATION.

• GIVEN

The heigt of a right circular cylinder = 6 m

Three times the sum of the area of its two

circular face is twice the area of the carved surface.

Find the radius of its base,

according to the question,

Let radius of the base be = r

Then,

3( πr^2 + πr^2 ) = 2 X 2rh

6πr^2 = 4πrh

6πr^2 = 4πr X 6

r = 4 m

Hence,

Radius of its base = 4m