Question

the height of a right circular cylinder is double of its radius.if the height will sixfold of radius,the volume o the cirular cylinder will539 decimeter cube .so what is the height of this cirular cylinder

Answer 1

case i) h = 2r
case ii) h2 = 6r + 2r

case ii) volume = πr²h
539 = 22/7 * r² * 8r
49 = 16r³/7
343 = 16r³
16 = 343/r³ = (7/r)³
r = 7/³√16
h = 14 / ³√16

Answer 2

HELLO DEAR,

let the height of cylinder be h
and the radius be r


given that:-

h=2r-------(1)


if h=6r

THEN,
$\begin{lgathered}\begin{lgathered}\pi {r}^{2} h = 539 \\ = > \pi {r}^{2} 6r = 539 \\ = > {r}^{3} = \frac{539 \times 7}{22 \times 6} \\ = > {r}^{3} = \frac{3773}{132} \\ = > {r}^{3} = 28.5 \\ = > r = 3.05decimeter\end{lgathered}\end{lgathered}$

from --(1)


h=2×3.05

=> h=6.1 decimeter


I HOPE ITS HELP YOU DEAR,
THANKS