The height of a room is 5 metres and its length is twice its breadth. If 240 metres of paper of breadth 50 cm are required for papering its walls, find the area of the floor.
Answers
Answer:
Step-by-step explanation:
H = 5, L = 2B, Area of 4 = Area of wall paper
2(LH) + 2(BH) = 240 × 50/100
10L + 10 B = 24 × 5, 10L + 5L= 24 × 5
15 L = 24 × 5, L =24×5/15 = 8
L= 8, B = 4,
∴area of floor = L × B
= 8 × 4 = 32
Answer:
Area of the floor = 32 m²
Step-by-step explanation:
Given data
height of a room h = 5 meters
and its length is twice of its breadth
the paper requires for papering the walls = 240 meters with 50 cm breadth
⇒ 50 cm = 0.5 meters
the paper required = 240 m × 0.5 m
here we need to find area of the floor for that we will find length and breadth of the room
Let x be the breadth of the room
from given data length of the room = 2x
the surface area of the room walls = 2 (l+b) h
= 2 (2x + x) 5
= 2(3x ) 5 = 30x
the area of the paper required = length × breadth
= 240 m × 0.5 m
= 120 m
⇒ the area of the paper required = the surface area of the room walls
120 = 30x
x = 120 / 30
= 4 m
breadth of the room = 4 meters
length of the room = 2(4) = 8 meters
⇒ Area of the floor = l b
= 8 × 4 = 32 m²