The height of a solid right circular cylinder is 6 metres and three times the sum of the areas of its two end faces is twice the area of its curved surface. The radius of its base, in metre, is: (A) 4 (B)2 (C) 8 (D) 10
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Answer:
a) 4
Step-by-step explanation:
h = 6m
formula for area of end face of cylinder= πr^2
formula for curved surface area of cylinder = 2πrh
3 (πr^2 + πr^2) = 2 (2πrh)
the solving is attached
hope you understand!
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