The height of a tower is 12 m. What is the length of its shadow when 10 Sun’s altitude is 45°? Solution:
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Let AB be the tower Fig.
Then, ∠C=45°
, AB=12 m
tan45° = AB/BC
= 12/BC
⇒1= 12/BC
⇒BC=12 m
∴ The length of the shadow is 12 m.
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