The height of a triangle is increased by 30%. What can be
the maximum percentage increase in length of the base
so that the increase in area is restricted to a maximum of
90% ?
Answers
Answered by
4
Answer:
Let the height be h and base be b.
Height increases 40%,So new height = h + 40% of h =7/5*h
Area of triangle = (½ * h * b)
Area increases by 60%. so, new area,
= (½ * h * b) + 60% of (½ * h * b)
=8/5*1/2*b*h
Let new base be x, then
New area,=1/2*7/5*x=8/5*1/2*b*h
which will result into x=8/7*b
So, base will increase by 1/7th of b=14.2
Answered by
3
Answer:
Let the height be h nd base be b
Height increases 40%, so new height = h+40% of h=7/5*h
Area of triangle= (1/2*h*b)
Area increases by 60% so , new area,
=(1/2*h*b)+60% of (1/2*h*b)
=8/5*1/2*h*b
Let new base be x, then
New area,=1/2*7/4*x
⠀⠀⠀⠀⠀⠀ =8/5*1/2*b*h
Which will result into x= 8/7*b
So, base will increase by 1/7th of b=14.2
❤️xXMissMarshmallowXx❤️⠀
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