Question

the height of an equilateral triangle measure 9√3cm. find its area.​

Answer 1

Height

$= \sqrt{3} \div 2 \times a$

$9 \sqrt{3} = \sqrt{3} \div 2 \times a$

$a = 9 \div 2 = 4.5$

Area

$= \sqrt{3} \div 4 \times {a}^{2}$

$= \sqrt{3} \div 4 \times 9 \times 9 \div 2 \div 2$

$= 81 \sqrt{3}$

The area is 81✓3cm².

Answer 2

same this u can find the answer of your question bro