The height of mercury column in a barometer in a calcutta
Answers
Explanation:
Given ⇒
Height of the Mercury Column in a Barometer = 75 cm.
For Finding the Pressure in S.I. System, Changing 75 cm into meter.
∴ Height of the Mercury column(h) = 75 cm.
= 0.75 m.
Acceleration due to gravity(g) = 9.8 m/s².
Density of the Water = 10³ kg/m³.
= 1000 kg/m³
Specific Gravity of the Mercury = 13.6
Specific Gravity of the Substance is the Ratio of the Density of the Substance to the Density of the Water.
∴ Specific Gravity = Density of the Substance /Density of the Water.
⇒ Density of the Mercury(ρ) = 1.3 × 1000
= 1300 kg/m³.
Now,
Using the Formula,
Pressure(P) = hρg
= 0.75 × 1300 × 9.8
= 9555 Pa.
Hence, the Pressure is 9555 Pa.
For Finding the Pressure in C.G.S. System,
Height of the Mercury Column(h) = 75 cm.
Acceleration due to gravity(g) = 9.8 m/s²
= 9.8 × 100 cm/s².
= 980 cm/s².
Density of the Water = 1000 kg/m³.
= 1000 × 10³g/10⁶ cm³.
= 10⁶/10⁶ g/cm³.
= 1 g/cm³
∴ Density of the Mercury(ρ) = Specific Gravity of the Mercury × Density of the Water.
= 1.3 × 1
= 1.3 g/cm³.
Now Using the Formula,
Pressure(P)= hρg
= 75 × 1.3 × 980
= 9550 Ba.
Hence the Pressure is 9550 barye.
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