Question

the height of the triangle is increased by 10%. TO retain the original area of the triangle, its corresponding base must be decreased by how much?

Answer 1

hope this helps........

Answer 2

Answer:

9%

Step-by-step explanation:

Let A be the area, b be the the base and h be the height of the original triangle.

$A=\frac{1}{2}bh$

Now, height of the triangle is increased by 10%.

Thus, the new height is

h ' = h + 0.1 h

h ' = 1.1 h

Now, the area remains same. So, we have

$\frac{1}{2}bh=\frac{1}{2}b'(1.1h)\\\\b'=\frac{1}{1.1}b\\\\b'=0.91b\\\\b'=(1-0.09)b$

Thus, we can conclude that the base is decreased by 9%.