The height of two vertical poles are 28 m and 18 m respectively. If the distance between their feet is 24 m, find the distance between their tops.
Answers
Given that height of one vertical pole = 28 m.
Given that height of another vertical pole = 18 m.
The difference in their height = (28 - 18)
= 10 m.
Given that the distance between their feet is 24 m.
Now,
By Pythagoras theorem, we know that
⇒ (H)^2 = (Base)^2 + (Perpendicular)^2
⇒ (H)^2 = (24)^2 + (10)^2
⇒ (H)^2 = 676
⇒ H = √676
⇒ H = 26 m
Therefore, the distance between the tops of of the poles is 26 m.
Hope it helps!
Step-by-step explanation:
ANSWER
Height of two poles are 36 m and 28 m. Distance between their tips is 17 m.
The difference between their heights = 36 - 28 = 8 m
Consider it as a right angle triangle, with distance between their tips being the hypotenuse, difference in heights being the perpendicular and the distance between their foot being the base.
Thus, H
2
=P
2
+B
2
17
2
=8
2
+B
2
289=64+B
2
B
2
=225
B=15 m
Hence, distance between their foot is 15 m