Question

the height of water in a vessel is h. the vessel wall of width b is at an angle theta to the vertical. the net force exerted by the wall is

Answer 1

Answer:

1/2  ρbh ^2  gsecθ

Explanation:

z=ysecθ   ⇒   dz=dysecθ

P=(ρgy)

dA=(b)dz=(b)dysecθ

dF=PdA=(ρgbsecθ)ydy

∴   F=∫  ^(h) 0  dF=  1/2  ρbh ^2  gsecθ

HOPE IT HELPS !