Question

the height y and distance x along the horizontal, for a body projected in the vertical plane are given by y=8t-5t², x=6t. find the initial velocity of body

Answer 1

t= x/ 6.
put it in eqn of y to get => y= 4/3x - 5/36 x^2.
Compare it with eqn of trajectory
y= xtan theta - gx^2/ 2u^2 cos^2 theta
to get u and theta