The height y and horizontal distance x covered by a projectile in a time t sec are given by equation y=8t-5t^2 and x=6t if x and y are measured in meters the velocity of projectile is
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Answer:10ms⁻1
Explanation:y = 8t - 5t²
From this equation
uSinθ = 8 ———(1)
x = 6t
From this equation
uCosθ = 6 ———(2)
Square and add equations (1) and (2)
u² (Sin²θ + Cos²θ) = 8² + 6²
u² = 100
u = 10m/s
Velocity of projection is 10m/s
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