The heights (in cm) of 30 students of class IX are given below:
155, 158, 154, 158, 160, 148, 149, 150, 153, 159, 161, 148, 157, 153, 157, 162, 159, 151, 154, 156, 152, 156, 160, 152, 147, 155, 163, 155, 157, 153
Prepare a frequency distribution table with 160-164 as one of the class intervals.
Answers
The frequency distribution table with 160-164 as one of the class intervals is shown below.
Given,
The class size = 164 - 160 = 4
From given we have,
The maximum value of the height of the students = 163.
The minimum value of the height of the students = 147
The range = 163 - 147 = 16
The lower limit of the first class interval
a - h/2 = 147 - 4/2 = 145
The upper limit of the first class interval
a + h/2 = 147 + 4/2 = 149
Therefore, the frequency distribution in which the upper limit is excluded and the lower limit is included is
Height Frequency
144 - 148 1
148 - 152 5
152 - 156 10
156 - 160 9
160 - 164 5
Total 30