The hemispherical bowl made ul of the radius 7 cm ( inner radius) find the cost of polishing the inner portion of the bowl at the rate of ₹10 per 100 m2
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Radius of bowl =7cm
Inner CSA of bowl = 2πr^2
=2×22/7×7×7
=308cm^2
Now the cost of polishing 100cm^2 area= Rs10
so the cost of polishing 308cm^2 area
Rs(10/100×308)
Rs30.80
Inner CSA of bowl = 2πr^2
=2×22/7×7×7
=308cm^2
Now the cost of polishing 100cm^2 area= Rs10
so the cost of polishing 308cm^2 area
Rs(10/100×308)
Rs30.80
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