Question

the hieght of a parallelogram is three - eighths of its base if the area of the parallelogram is 96 cm^ find it's hieght and base​

Answer 1

Answer:

Let b be the base of the parallelogram.

Height of parallelogram (h)=

8

3

b

Area of parallelogram =

2

1

×b×h=96cm

2

(Given)

⇒

2

1

×b×

8

3

b=96

⇒b

2

=

3

96×8×2

⇒b=

512

=16

2

cm

Therefore,

h=

8

3

×16

2

=6

2

cm

Answer 2

Step-by-step explanation:

Area of parallelogram is A = bh

given, h = 3/8 b

then A = 3/8 b^2

by substituting A = 96 we get b = 16.

then h = 6