The high of elevation of the top of the building of the distance of 50 M from its foot horizontal plane to found to be 60 degree. Find the high of the building.
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answer is in photo plz see it
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Here u go ♥️♥️♥️✨ ✨✨ ✨
Given : BC,base=50m ; Elevation=60°
tan60°=√3
So, Now using formula we get ,
⏩⏩⏩
tan 60°=AB/Bc
=> √3=AB/50
=> 50√3=AB.⏪⏪⏪⏪
Therefore AB, height of tower = 50√3m.
Hope it helps u.........✌️♥️♥️♥️✌️✌️✌️✌️
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