Question

The hollow cylinder of height 14 cm has an outer
diameter of 7cm and thickness of 1 cm. Find its total
surface area​

Answer 1

Answer:

h = 14 cm

R = 7 / 2

Thickness = 1cm

$r = \frac{7}{2} - 1$

$= \frac{7 - 2}{2}$

$= \frac{5}{2}$

TSA = 2 pi ( R + r ) ( R - r + h )

$= 2 \times \frac{22}{7} ( \frac{7}{2} + \frac{5}{2} )( \frac{7}{2} - \frac{5}{2} + 1)$

$= 2 \times \frac{22}{7} ( \frac{12}{2} )(2)$

$= \frac{1056}{14}$

TSA= 75.42

I hope it will help u mate

Answer 2

Concept

In mathematics, Cylinder is a three dimensional solid

Given

1) Hollow Cylinder

2) Height 14cm

3) Diameter 7cm

4) Thickness 1cm

Find

Total surface area

Solution

We are given that

h = 14

D = 7

R = 7/2

As it is a hollow cylinder

Internal radius = r

r = 7/2 - 1

r = 5/2

TSA = 2π(R+r)(R-r + h)

= 2 * 22/7 (7/2 +5/2)(7/2 - 5/2 + 14)

= 44/7 * 6 * 15

=75.42

The Total Surface Area of hollow cylinder height 14 cm with an outer

diameter of 7cm and thickness of 1 cm is 75.42cm²

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