Question

the horizontal and vertical components of a force is 5N and 12N respectively. The force is-

Answer 1

Answer:

Net F=√F1^2 +F2^2+2F1F2cos©

The required answer is net F= √5^2+12^2

F=13N

Explanation:

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Answer 2

Force is 13N  if horizontal and vertical components of a force is 5N and 12N

Explanation:

Let say Net force is   F N making angle θ  with Horizontal axis

Horizontal Component = FCosθ N

Vertical Component = FSinθ   N

Horizontal Component = 5 N

Vertical Component = 12 N

FCosθ = 5

FSinθ = 12

Squaring both & adding

=> F²Cos²θ +  F²Sin²θ = 5² + 12²

=> F²(Cos²θ +  Sin²θ) = 25 + 144

=> F² (1) = 169

=> F²   = 13²

=> F = 13

Force is 13N

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