Physics, asked by Anonymous, 1 year ago

The horizontal and vertical components of the initial velocity of a projectile are 10 m/s and 20 m/s respectively. What will be the horizontal range of the projectile

Answers

Answered by TPS

29

time of flight = 2v/g = 2×20/10 = 4s
Range = ut = 10×4 = 40m

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