the horizontal component of a force of 10 Newton inclined at 30 degree to vertical is
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Hey there!
The horizontal component will be Fsin theta
i.e 10sin30= 10×1/2=5N
Hope that helps you ✌️
The horizontal component will be Fsin theta
i.e 10sin30= 10×1/2=5N
Hope that helps you ✌️
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