Question

The horizontal distance between two poles is 15 m. The angle of depression of the top of first pole as

seen from the top of second pole is 30°. If the height of the second pole is 24 m, find the height of the

first pole. [Use √3 = 1.732]​

Answer 1

Answer:

AB is the first pole and CD is the second pole.

⇒ AC=AE=15m and CD=24m

⇒ AB=CE=xm

⇒ In △BDE,tan30

o

=

BE

DE

⇒

3

1

=

15

24−x

⇒ 15=24

3

−

3

x

⇒ x=

3

24

3

−15

⇒ x=

1.732

24×1.732−15

⇒ x=

1.732

41.568−15

=15.33m

∴ The height of the first pole is 15.33m

solution

Answer 2

Answer:

The answer is given to the picture.