The horizontal distance between two poles is 15 m. The angle of depression of the top of second pole as seen from the top of first pole is300 .If the height of the first pole. (use √3 = 1.732 )
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Answer:
⇒ AB is the first pole and CD is the second pole.
⇒ AC=AE=15m and CD=24m
⇒ AB=CE=xm
⇒ In △BDE,tan30
o
=
BE
DE
⇒
3
1
=
15
24−x
⇒ 15=24
3
−
3
x
⇒ x=
3
24
3
−15
⇒ x=
1.732
24×1.732−15
⇒ x=
1.732
41.568−15
=15.33m
∴ The height of the first pole is 15.33m
Step-by-step explanation:
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