Question

The horizontal distance between two poles is 15 m. The angle of depression of the top of first pole as seen from the top of second pole 30°. If the height of the second police 24m. Find the height of the first pole. (use root 3 = 1.732 ).

Answer 1

Step-by-step explanation:

let AB be the 1st pole and CD be the 2nd pole

AC=15m

CD=24m

let AB=x

CE=x

ED=24-x

consider triangle BED

tan30° = DE/BE

1/√3 = (24-x)/15

15= √3(24-x)

5√3 = 24-x

x = 24-5√3

 = 15.33m

Answer 2

HIII......

GOOD MORNING:-)

HERE IS YOUR ANSWER:--------

LET US 1ST POLE BE AB AND CD BE THE 2ND POLE.

AC= 15M

CD=24M

LET AB=X

CE= X

ED=24-X

CONSIDER TRIANGLE BED

TAN=30° = DE/BE

1ROOT 3=(24-x)/15

15= root 3(24-x)/15

5root 3= 24-x

x=24-5root 3.

=15.33m

HOPE THIS HELPS YOU.....

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