Question

The horizontal distance of a kite from the boy flying it is 30 m and 50 m of cord is out from the roll. if the wind moves the kite horizontally at the rate of 5 km per hour directly away from the boy, how fast is the cord being released?

Answer 1

Solution:

The horizontal distance  = 30 m

String = 50 m

Vertical distance = 40 m

Hypotenuse to ground distance ratio = 5/3

String released = $\frac{5}{3}\cdot \frac{5000}{3600}$

= $= 2.32 m/s$

Answer 2

Answer:

Cord Released at 2.31 m/sec approx.

Step-by-step explanation:

Hey Mate,

Given Data,

Horizontal distance = 30m,

String = 50m ,

The Vertical Distance = 40m ,

Kite rate horizontally = 5km /hr  => 5000m/3600 seconds

Hypotenuse to ground distance ratio = 5/ 3

String released at = (5/3) × ( 5000/3600)

=> 2.31 m/sec approx.

So,

The Cord Released at 2.31 m/ sec approx.