Question

The horizontal force (F) acting on a block of mass 1kg
varies with time (in S) as F = (2/9*t³)N if the coffiecient of friction between the block
and surface u=0.2 then the frictional force acting
the block at t=3s will be​

Answer 1

Answer:

ANSWER

Here, We know that

limiting friction, f=μmg⇒

We have,

μ=0.6,m=1kg,g=9.8ms

−2

∴ f=(0.6×1×9.8)=5.88N

Applied force ⇒F=ma=1×5=5N

As F<f, so force of friction =5N