Question

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

Answer 1

The relation between Horizontal range and Maximum height of the projectile is,

tanθ = 4H/R

Given, Horizontal range and the maximum height of a projectile are equal.

So, H = R

⇒ H/R = 1

Therefore,

⇒tanθ = 4H/R

⇒tanθ = 4(H/R)

⇒ tanθ = 4(1)

⇒ tanθ = 4

⇒θ = tan^-1(4)

Therefore, The angle of projection is tan^-1(4).

Answer 2

Answer:

The relation between Horizontal range and Maximum height of the projectile is,

tanθ = 4H/R

Given, Horizontal range and the maximum height of a projectile are equal.

So, H = R

⇒ H/R = 1

Therefore,

⇒tanθ = 4H/R

⇒tanθ = 4(H/R)

⇒ tanθ = 4(1)

⇒ tanθ = 4

⇒θ = tan^-1(4)

Therefore, The angle of projection is tan^-1(4).

Explanation: