Question

the horizontal range of a projectile field at an angle of 15 degree is 50 metre if it is fired with the same speed at an angle of 45 degree its range will be​

Answer 1

Explanation:

If it is fired with the same speed at an angle of 45^@ its range will be. 50=u2sin2×152gor u^2 /g = (50) /(sin 30^@) = (50)/(1//2) = 100R = 9u^2 sin 2 xx 45^2)/g = u^2/g = 100 m`.