Question

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now beings to blow in the direction of horizontal motion of projectile, giving to constant horizontal acceleration equal to g. Under the same conditions of projections , the new range will be (g = acceleration due to gravity)

Answer 1

Answer:

PHYSICS

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to blow in the direction of the motion of the projectile, giving it a constant horizontal acceleration of g/2. Under the same conditions of projection, the horizontal range of the projectile will now be

December 27, 2019avatar

Anurag Misanthropist

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ANSWER

Let the angle of projection be θ and speed of projectile be u.

Initially, horizontal component of velocity u

x

=ucosθ

Acceleration in horizontal direction a=

2

g

So, horizontal range of projectile R

′

=u

x

T+

2

1

aT

2

where T=

g

2usinθ

is the time of flight.

Or R

′

=(ucosθ)

g

2usinθ

+

4

g

×(

g

2usinθ

)

2

Or R

′

=

g

u

2

sin2θ

+2

2g

u

2

sin

2

θ

Using R=

g

u

2

sin2θ

and H=

2g

u

2

sin

2

θ

⟹ R

′

=R+2H